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Question:
\(\frac{\mathrm{3} }{\mathrm{(2x-1)}} - \frac{\mathrm{4} }{\mathrm{(5x+2)}}\) = _________.
A
\(\frac{\mathrm{(7x+10)} }{\mathrm{(2x-1) \times (5x+2)}}\)
explanation
Since this is a subtraction of 2 fractions with different denominators, determine their least common denominator, in this case, the LCD is: (2x-1)(5x+2)
Proceed to subtraction: \(\frac{\mathrm{3} }{\mathrm{(2x-1)}} - \frac{\mathrm{4} }{\mathrm{(5x+2)}}\)
\(\frac{\mathrm{[3(5x+2)-4(2x-1)]} }{\mathrm{(2x-1) \times (5x+2)}}\)
\(\frac{\mathrm{[15x+6-8x+4]} }{\mathrm{(2x-1) \times (5x+2)}}\)
\(\frac{\mathrm{(7x+10)} }{\mathrm{(2x-1) \times (5x+2)}}\)
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