A ball is kicked off the edge of a roof that is 34 meters tall. The horizontal speed given to the ball is 12.5 m/s. If there is no air resistance, how far out from the base of the building will the ball land?

This problem provides the vertical distance (height of the roof of the building), vertical acceleration (gravitational constant), and the initial horizontal velocity (speed of the ball).
Vx = Horizontal velocity (12.5 m/s)
dy= vertical displacement of the object (34 m)
dx = unknown (this is what we are solving for)
t = time = sqrt(2 × height / 9.81)
\(a=9.8 m/s^2\)
Since we assume there is no air resistance, dx = Vx t.
dx = vxt
\(dx= 12.5m/s \times 2.63s\)
dx = 32.86 m
Since there is no air resistance, the ball will land 32.86 m from the building.