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Question:
Solve: \(\frac{\mathrm{c+11} }{\mathrm{9}} = \frac{\mathrm{9+c} }{\mathrm{7}}\)
A
-2
explanation
Cross multiplying we get:
\(7 (c +11) = 9 (9 + c)\)
Distributing we get:
\(7c + 7(11) = 9(9) + 9c\)
Subtracting 9c and 77 from both sides we get:
\(7c + 77 - 9c - 77 = 81 + 9c - 9c - 77\)
⇒ \(-2c = 4\)
Dividing both sides with \(-2\) we get:
=> \(c = -2\)
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