What is \(4\frac{\mathrm{3} }{\mathrm{8}} +2\frac{\mathrm{2} }{\mathrm{7}}\)?

The whole numbers (4 and 2) are first added together to get 6, and then a common denominator must be found for the fractions. 8 multiplied by 7 equals 56, which will be the common denominator in this equation. Whatever is done to the denominator must also be done to the numerator, so: \(\frac{\mathrm{3} }{\mathrm{8}} = \frac{\mathrm{21} }{\mathrm{56}}\) and \(\frac{\mathrm{2} }{\mathrm{7}} = \frac{\mathrm{16} }{\mathrm{56}}\)
Since the denominators are now the same, you can just add the numerators: \(\frac{\mathrm{21} }{\mathrm{56}} + \frac{\mathrm{16} }{\mathrm{56}} = \frac{\mathrm{37} }{\mathrm{56}}\)
Add the whole number, 6, from the beginning and you have \(6\frac{\mathrm{37} }{\mathrm{56}}\)