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Question:
To find the magnitude of the resulting force between the two objects, use Coulomb’s Law: \(F=k \frac{\mathrm{ Q_1 Q_R } }{\mathrm{r^2}} \)
Q1 = the charge on the point-like object one (unit of measure is Coulomb, C)
Q2 = the charge on the point-like object two (unit of measure is Coulomb, C)
r = the distance between the two objects (unit of measure is meter, m)
k = the proportionality constant, which is \(9 \times 10^9N \times m^2c^2\)
Step 1: Convert μC to C and convert centimeters to meters
\(45 \mu C = 45 \times 10^{-6}C\)
\(30 \mu C = 30 \times 10^{-6}C\)
Step 2: Insert the values into the equation
Q1=\(45 \times 10^{-6}C\)
Q2=\(30 \times 10^{-6}C\)
r=0.60
\(F=9 \times 10^9N \times m^2c^2 \frac{\mathrm{45 \times 10^{-6} \times 30 \times 10^{-6}} }{\mathrm{(0.60)^2}} = 33.75N\)
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