What would be the magnitude of resulting force between an object of charge 45μC and another object of charge 30μC that are placed 60 cm apart?

To find the magnitude of the resulting force between the two objects, use Coulomb’s Law: \(F=k \frac{\mathrm{ Q_1 Q_R } }{\mathrm{r^2}} \)
Q1 = the charge on the point-like object one (unit of measure is Coulomb, C)
Q2 = the charge on the point-like object two (unit of measure is Coulomb, C)
r = the distance between the two objects (unit of measure is meter, m)
k = the proportionality constant, which is \(9 \times 10^9N \times m^2c^2\)
Step 1: Convert μC to C and convert centimeters to meters
\(45 \mu C = 45 \times 10^{-6}C\)
\(30 \mu C = 30 \times 10^{-6}C\)
Step 2: Insert the values into the equation
Q1=\(45 \times 10^{-6}C\)
Q2=\(30 \times 10^{-6}C\)
r=0.60
\(F=9 \times 10^9N \times m^2c^2 \frac{\mathrm{45 \times 10^{-6} \times 30 \times 10^{-6}} }{\mathrm{(0.60)^2}} = 33.75N\)