Scan QR code or get instant email to install app

Skip to content
#
For a skewed distribution that has excess kurtosis, the minimum percentage of the distribution within three standard deviations of the mean is closest to:

### Related Information

Question:

A
89%.

explanation

Chebyshev's inequality holds regardless of the shape of the distribution. For any k > 1, the minimum percentage of the distribution within k standard deviations of the mean is 1 − 1/k . Thus, for 3 standard deviations, the percentage is ≥ 1 − 1/9 = 89%.

Take more free practice tests for other PASSEMALL topics with our cfa level 1 sample questions now!

Comments