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Question:
1212Begin by factoring the first expression and rewriting the division as an inverse multiplication:
The function shows a discontinuity at x = 2 and x = -3. It shows a vertical asymptote at x = -1.
To find the excluded range values corresponding to the discontinuities, substitute the x values into the reduced function: . So:
and
Solving the function for x enables another excluded range value to be found:
, which gives
, so y \u2260 0
From the reduced function: , it can be seen that as x increases, f(x) approaches 0, and that as x approaches -1 from the right, f(x) approaches infinity. As x decreases, f(x) approaches 0, and as x approaches -1 from the left, f(x) approaches negative infinity.
Lastly, the y intercept: , giving the point (0, 1)
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